If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+10.8x-63=0
a = 1; b = 10.8; c = -63;
Δ = b2-4ac
Δ = 10.82-4·1·(-63)
Δ = 368.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10.8)-\sqrt{368.64}}{2*1}=\frac{-10.8-\sqrt{368.64}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10.8)+\sqrt{368.64}}{2*1}=\frac{-10.8+\sqrt{368.64}}{2} $
| n-(-7)=-12 | | 6=-1/3x+13 | | -14-10y+10y=-14 | | 32=(s)(4) | | -14-10+10y=-14 | | (g))4)=24 | | (g))4)=2- | | 3x-1=4(x+2) | | 7y-7=30 | | -4x+13=-6x+25 | | 11x+21=-4x-9 | | -23=-2x-3 | | 7x+22=-3x-28 | | 320=4x | | -2x+16=-3x+21 | | -9x+12=3x-12 | | 5x-5=-x+25 | | 2x+12=5x+9 | | 2m-22=10 | | 1/4(8+4x)+3=2.5x-4 | | 2x+3=2(5x+3) | | -14+3x=26 | | 3/10x+1.4=-x+2 | | 3(2x-3(=4x-5 | | 2x(x-6)=x-14 | | 0=8m+28400 | | 0.1(x+20)-0.04(x-10)=4.8 | | 7/2x+5/4=2+1/6x | | 7x-10=2x+3- | | 5c+2/c=6 | | 27a=1161 | | 3x-5+6x=4 |